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Refacto lsbset.hide to use less memory
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1 changed files with 10 additions and 10 deletions
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@ -25,6 +25,7 @@ __date__ = "$Date: 2016/03/13 $"
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__revision__ = "$Date: 2019/05/31 $"
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__license__ = "GPLv3"
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import sys
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from typing import IO, Iterator, Union
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from PIL import Image
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@ -56,7 +57,7 @@ def hide(
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raise Exception("Not a RGB image.")
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img = img.convert("RGB")
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img_list = list(img.getdata())
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encoded = img.copy()
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width, height = img.size
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index = 0
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@ -76,7 +77,12 @@ def hide(
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while index + 3 <= len_message_bits:
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generated_number = next(generator)
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r, g, b, *a = img_list[generated_number]
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col = generated_number % width
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row = int(generated_number / width)
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coordinate = (col, row)
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r, g, b, *a = encoded.getpixel(coordinate)
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# Change the Least Significant Bit of each colour component.
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r = tools.setlsb(r, message_bits[index])
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@ -85,18 +91,12 @@ def hide(
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# Save the new pixel
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if img.mode == "RGBA":
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img_list[generated_number] = (r, g, b, *a)
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encoded.putpixel(coordinate, (r, g, b, *a))
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else:
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img_list[generated_number] = (r, g, b)
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encoded.putpixel(coordinate, (r, g, b))
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index += 3
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# create empty new image of appropriate format
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encoded = Image.new(img.mode, (img.size))
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# insert saved data into the image
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encoded.putdata(img_list)
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return encoded
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